Compute the Max

 define o_max and assign i_intaryTb[0];

  looping from 0 to i_intaryTb.length -1 ,index += i_one_stepLength

      if ( index >= i_intaryTb.length ) then

          break the looping;

      if ( i_intaryTb[index] > o_max ) then

          o_max = i_intaryTb[index];

      end if

  end looping

  return o_max;

So, I got a lot of help with this from my friend Google. I'm not necessarily anywhere near good at programming, but it seems that I can understand this enough to argue that it will terminate and produce the correct results. 

i is assigned the length once it reaches i it stops. 

it will keep going until the max is found, or i is reached.


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